bentuk rasional dari 2√5/√5-2 adalah
+ caranya
+ caranya
[tex]\frac{2\sqrt{5}}{\sqrt{5}-2} \\\\=\frac{2\sqrt{5}}{\sqrt{5}-2}\times{\frac{\sqrt{5}+2}{\sqrt{5}+2}}\\\\=\frac{2\sqrt{5}(\sqrt{5}+2)}{(\sqrt{5})^{2}-2^{2}}\\\\=\frac{2\sqrt{5}\times\sqrt{5}+2\sqrt{5}\times2}{5-4}\\\\=\frac{2\times5+4\sqrt{5}}{1}\\\\=10+4\sqrt{5}[/tex]
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